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NEW QUESTION: 1
A company expects the U.S. dollar to depreciate in value compared to the British pound. The company will have a British pound payment to make in five months. The company would MOST LIKELY buy:
A. a U.S. dollar call.
B. a British pound call.
C. a British pound put.
D. a U.S. dollar put.
Answer: B

NEW QUESTION: 2
The customer is still not convinced about the advantages of using node VIPs. Which is the most important point that will convince him about why VIPs are used in Oracle RAC 12cR1 environments?
A. Configuring VIP is optional and not needed in an Oracle RAC 12cR1 configuration.
B. It is very convenient as whenever a node/interface/network related to the node VIP fails, the VIP can fail to another node and the failed over VIP can start accepting connections from the new node avoiding connection failures
C. It is needed as whenever the node/interface/network related to the VIP fails, nothing happens and node VIP never fails to any other node and stays stable
D. This is needed as whenever a node/interface/network related to the node VIP fails, clients that attempt to connect to the VIP address receive a rapid connection-refused error instead of waiting for TCP connect timeout messages. This helps for a quicker failure detection and resolution
Answer: B

NEW QUESTION: 3
The use of two-factor authentication is NOT a requirement on PCI DSS v3 for remote network access originating from outside the network by personnel and all third parties.
A. False
B. True
Answer: A

NEW QUESTION: 4
You need to display the first names of all customers from the CUSTOMERS table that contain the character 'e' and have the character 'a' in the second last position.
Which query would give the required output?
A. SELECT cust_first_name FROM customers WHERE INSTR(cust_first_name, 'e')<>0 AND SUBSTR(cust_first_name, LENGTH(cust_first_name),-2)='a';
B. SELECT cust_first_name FROM customers WHERE INSTR(cust_first_name, 'e')IS NOT NULL AND SUBSTR(cust_first_name, 1,-2)='a';
C. SELECT cust_first_name FROM customers WHERE INSTR(cust_first_name, 'e')<>0 AND SUBSTR(cust_first_name, -2, 1)='a';
D. SELECT cust_first_name FROM customers WHERE INSTR(cust_first_name, 'e')<>'' AND SUBSTR(cust_first_name, -2, 1)='a';
Answer: C
Explanation:
The SUBSTR(string, start position, number of characters) function accepts three parameters and
returns a string consisting of the number of characters extracted from the source string, beginning
at the specified start position:
substr('http://www.domain.com',12,6) = domain
The position at which the first character of the returned string begins.
When position is 0 (zero), then it is treated as 1.
When position is positive, then the function counts from the beginning of string to find the first
character.
When position is negative, then the function counts backward from the end of string.
substring_length
The length of the returned string. SUBSTR calculates lengths using characters as defined by
theinput character set. SUBSTRB uses bytes instead of characters. SUBSTRC uses Unicode
complete characters.
SUBSTR2 uses UCS2 code points. SUBSTR4 uses UCS4 code points.
When you do not specify a value for this argument, then the function
The INSTR(source string, search item, [start position],[nth occurrence of search item]) function
returns a number that represents the position in the source string, beginning from the given start
position, where the nth occurrence of the search item begins:
instr('http://www.domain.com','.',1,2) = 18