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NEW QUESTION: 1
The gas price is a value set by the creator of the blockchain transaction? Select best answer.
A. Its Negotiable
B. FALSE
C. TRUE
Answer: C
Explanation:
Explanation/Reference:
Explanation:
The gas price is a value set by the creator of the transaction, who has to pay gas_price * gas up front from the sending account. If some gas is left after the execution, it is refunded in the same way. If the gas is used up at any point (i.e. it is negative), an out-of-gas exception is triggered, which reverts all modifications made to the state in the current call frame.
Reference: https://solidity.readthedocs.io/en/latest/introduction-to-smart-contracts.html#the-ethereum- virtual-machine

NEW QUESTION: 2
Refer to the exhibit.

A large hospital chain has approached you to redesign their storage infrastructure. The head of IT believes their requirement is for 100 TB of RAW capacity. They want to consolidate their PACS, file shares and home directories onto one cluster and require very fast enumeration of the directories. The following are the notes from meetings with the department heads.
Which is the best cluster configuration that meets the customer's requirements?
A. 5 x S-Series nodes
B. 3 x S-Series nodes using SmartPools and 3 x NL-Series nodes for Archive
C. 3 x NL-Series nodes using SynqIQ to 3 x NL-Series nodes
D. 4 x X-Series nodes using SynqIQ to 4 x NL-Series nodes
Answer: D

NEW QUESTION: 3
Standard III of the Standards of Professional Conduct deals with Relationships with and Responsibilities to
________.
A. the Employer
B. None of these answers
C. Clients and Prospects
D. AIMR
Answer: A
Explanation:
Explanation/Reference:
Explanation:
Standard III of the Standards of Professional Conduct deals with Relationships with and Responsibilities to the Employer.

NEW QUESTION: 4

A. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
B. SELECT Id, Name, Marks,
DENSE_RANK() OVER(ORDER BY Marks DESC) AS Rank
FROM StudentMarks
C. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER(PARTITION BY StudentCode ORDER BY Marks DESC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
D. SELECT StudentCode as Code,
NTILE(2) OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
E. SELECT StudentCode as Code,
DENSE_RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
F. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY SubjectCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
G. SELECT StudentCode AS Code,Marks AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK() OVER(PARTITION BY StudentCode ORDER BY Marks ASC) AS Rank
FROM StudentMarks) tmp
WHERE Rank = 1
H. SELECT StudentCode as Code,
RANK() OVER(ORDER BY AVG (Marks) DESC) AS Value
FROM StudentMarks
GROUP BY StudentCode
Answer: H
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/ms189798.aspx