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NEW QUESTION: 1
You work as an administrator at Contoso.com. The Contoso.com network consists of a single domain named Contoso.com. All servers in the Contoso.com domain, including domain controllers, have Windows Server
2012 R2 installed.
You have been instructed to make sure that Contoso.com users are not able to install a Windows Store application. You then create a rule for packaged apps.
Which of the following is the rule based on? (Choose all that apply.)
A. The name of the application
B. The package version.
C. The publisher of the application.
D. The publisher of the package.
E. The application version.
F. The name of the package
Answer: B,D,F
Explanation:
Explanation
Packaged apps (also known as Windows 8 apps) are new to Windows Server 2012 R2 and Windows 8.
They are based on the new app model that ensures that all the files within an app package share the same identity. Therefore, it is possible to control the entire application using a single AppLocker rule as opposed to the non-packaged apps where each file within the app could have a unique identity. Windows does not support unsigned packaged apps which implies all packaged apps must be signed.
AppLocker supports only publisher rules for Packaged apps.
A publisher rule for a Packaged app is based on the following information:
Publisher of the package
Package name
Package version
All the files within a package as well as the package installer share these attributes. Therefore, an AppLocker rule for a Packaged app controls both the installation as well as the running of the app. Otherwise, the publisher rules for Packaged apps are no different than the rest of the rule collections; they support exceptions, can be increased or decreased in scope, and can be assigned to users and groups.

NEW QUESTION: 2
Huawei's evaluation & optimization service products can help customers improve network performance and drive household products.
A. Long-term positive (correct r
B. False
Answer: A

NEW QUESTION: 3
Scenario

An administrator is trying to ping and telnet from Switch to Router with the results shown below:

Click the console connected to RouterC and issue the appropriate commands to answer the questions.
For this question we only need to use the show running-config command to answer all the questions below:
Router>enable
Router#show running-config




What would be the effect of issuing the command access-group 115 in on the s0/0/1 interface?
A. FTP, FTP-DATA, echo, and www would work but telnet would fail
B. Telnet and ping would work but routing updates would fail.
C. No host could connect to Router through s0/0/1
D. Only traffic from the 10.4.4.0 network would pass through the interface
Answer: C
Explanation:
Explanation/Reference:
Explanation:

The above command will only the IP (0.0.0.0). Also there is no such IP address exists.
The wildcard mask of access-list 115 is 255.255.255.0, means that only host with IP addresses x.x.x.0 will be accepted. If the 4th part of an IP address is 0, then definitely it would be a network address. So no host can communicate with other network using S0/0/1 interface.
But it will accept the packet with source IP address - 10.10.0.0/8. The 4th octet is 0, and is not a network address but a valid IP address. So confusion... confusion... Anyhow other 3 choices (B, C, D) will definitely not the answer and Choice A is closest to the result, So the Answer is A.