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NEW QUESTION: 1
When should a post-mortem review meeting be held after an intrusion has been properly taken care of?
A. Within the first week of completing the investigation of the intrusion.
B. Within the first week after prosecution of intruders have taken place, whether successful or not.
C. Within the first three months after the investigation of the intrusion is completed.
D. Within the first month after the investigation of the intrusion is completed.
Answer: A
Explanation:
A post-mortem review meeting should be held with all involved parties within
three to five working days of completing the investigation of the intrusion. Otherwise,
participants are likely to forget critical information. Even if it enabled an organization to
validate the correctness of its chain of custody of evidence, it would not make sense to wait
until prosecution is complete because it would take too much time and many cases of
intrusion never get to court anyway.
Source: ALLEN, Julia H., The CERT Guide to System and Network Security Practices,
Addison-Wesley, 2001, Chapter 7: Responding to Intrusions (page 297).

NEW QUESTION: 2
The project manager has the following information about the estimated duration for an activity:
- Most likely [tM] - 15 days
- Pessimistic [tP] - 20 days
- Optimistic [tO] - 10 days
What is the estimated duration of this activity, according to the triangular distribution technique?
A. 5 days
B. 12.5 days
C. 15 days
D. 10 days
Answer: B

NEW QUESTION: 3
When running the following CMIS query "SELECT * FROM cmis:document WHERE CONTAINS('zebra')", what result would be returned?
A. All document objects with the word 'zebra' in the title property.
B. All document objects with the word 'zebra' in the description property only.
C. All document objects with the word 'zebra' in the name property.
D. All document objects with the word 'zebra' in the name, title or description properties
E. All document objects with the word 'zebra' in the full text content.
Answer: E
Explanation:
References:
https://books.google.com.pk/books?id=aCAHMyCi38EC&pg=PT531&lpg=PT531&dq=alfresco+SELECT+*+FROM+cmis:document&source=bl&ots=QEKmXF6kZt&sig=u3YgzKI45_IiPG8DtmqY4_t8OT0&hl=en&sa=X&ved=2ahUKEwjU1bCb6OXdAhVBdhoKHS69BgQQ6AEwAnoECAcQAQ#v=onepage&q=alfresco%20SELECT%20*%20FROM%20cmis%3Adocument&f=false

NEW QUESTION: 4
See the solution below
Explanation/Reference:
There are two ways to configure interVLAN routing in this case:
+ Use RouterC as a "router on a stick" and SwitchC as a pure Layer2 switch. Trunking must be established between RouterC and SwitchC.
+ Only use SwitchC for interVLAN routing without using RouterC, SwitchC should be configured as a Layer
3 switch (which supports ip routing function as a router). No trunking requires.
The question clearly states "No trunking has been configured on RouterC" so RouterC does not contribute to interVLAN routing of hosts H1 & H2 -> SwitchC must be configured as a Layer 3 switch with SVIs for interVLAN routing.
We should check the default gateways on H1 & H2. Click on H1 and H2 and type the "ipconfig" command to get their default gateways.
Answer:
Explanation:
\>ipconfig
We will get the default gateways as follows:
Host1:
+ Default gateway: 190.200.250.33
Host2:
+ Default gateway: 190.200.250.65
Now we have enough information to configure SwitchC (notice the EIGRP AS in this case is 650) Note: VLAN2 and VLAN3 were created and gi0/10, gi0/11 interfaces were configured as access ports so we don't need to configure them in this sim.
SwitchC# configure terminal
SwitchC(config)# int gi0/1
SwitchC(config-if)#no switchport -> without using this command, the simulator does not let you assign IP address on Gi0/1 interface.
SwitchC(config-if)# ip address 10.10.10.2 255.255.255.0 ->RouterC has used IP 10.10.10.1 so this is the lowest usable IP address.
SwitchC(config-if)# no shutdown
SwitchC(config-if)# exit
SwitchC(config)# int vlan 2
SwitchC(config-if)# ip address 190.200.250.33 255.255.255.224
SwitchC(config-if)# no shutdown
SwitchC(config-if)# int vlan 3
SwitchC(config-if)# ip address 190.200.250.65 255.255.255.224
SwitchC(config-if)# no shutdown
SwitchC(config-if)#exit
SwitchC(config)# ip routing (Notice: MLS will not work without this command) SwitchC(config)# router eigrp 65010
SwitchC(config-router)# network 10.10.10.0 0.0.0.255
SwitchC(config-router)# network 190.200.250.32 0.0.0.31
SwitchC(config-router)# network 190.200.250.64 0.0.0.31
NOTE: THE ROUTER IS CORRECTLY CONFIGURED, so you will not miss within it in the exam, also don't modify/delete any port just do the above configuration. Also some reports said the "no auto-summary" command can't be used in the simulator, in fact it is not necessary because the network 190.200.0.0/16 is not used anywhere else in this topology.
In order to complete the lab, you should expect the ping to SERVER to succeed from the MLS, and from the PCs as well.
Also make sure you use the correct EIGRP AS number (in the configuration above it is 650 but it will change when you take the exam) but we are not allowed to access RouterC so the only way to find out the EIGRP AS is to look at the exhibit above. If you use wrong AS number, no neighbor relationship is formed between RouterC and SwitchC.
In fact, we are pretty sure instead of using two commands "network 190.200.250.32 0.0.0.31″ and "network
190.200.250.64 0.0.0.31″ we can use one simple command "network 190.200.0.0″ because it is the nature of distance vector routing protocol like EIGRP: only major networks need to be advertised; even without
"no auto-summary" command the network still works correctly. But in the exam the sim is just a flash based simulator so we should use two above commands, just for sure. But after finishing the configuration, we can use "show run" command to verify, only the summarized network 190.200.0.0 is shown.